On Thu, Sep 04, 2025 at 10:56:44AM +0100, Kiryl Shutsemau wrote:
> On Wed, Sep 03, 2025 at 08:46:29PM -1000, Joey Pabalinas wrote:
> > Since `((a & (b|c)) == (b|c))` is the same thing as `(a & (b|c))`, use
> > the second version which is simpler.
> 
> Huh? No it is not the same thing.
> 
> a = 1;
> b = 1;
> c = 2;
> 
> (a & (b|c)) is 1 which is true.
> ((a & (b|c)) == (b|c)) is false.

Ah, you are right. My mistake.

-- 
Cheers,
Joey Pabalinas