Re: [PATCH] mm, slub: print CPU id on slab OOM

[Vlastimil Babka <vbabka@suse.cz>]

On 8/7/24 01:26, Axel Rasmussen wrote:
> Depending on how remote_node_defrag_ratio is configured, allocations can
> end up in this path as a result of the local node being OOM, despite the
> allocation overall being unconstrained (node == -1).
> 
> When we print a warning, printing the current CPU makes that situation
> more clear (i.e., you can immediately see which node's OOM status
> matters for the allocation at hand).
> 
> Signed-off-by: Axel Rasmussen <axelrasmussen@google.com>

Added to slab/for-next, thanks.

> ---
>  mm/slub.c | 3 ++-
>  1 file changed, 2 insertions(+), 1 deletion(-)
> 
> diff --git a/mm/slub.c b/mm/slub.c
> index c9d8a2497fd6..7148047998de 100644
> --- a/mm/slub.c
> +++ b/mm/slub.c
> @@ -3422,7 +3422,8 @@ slab_out_of_memory(struct kmem_cache *s, gfp_t gfpflags, int nid)
>  	if ((gfpflags & __GFP_NOWARN) || !__ratelimit(&slub_oom_rs))
>  		return;
>  
> -	pr_warn("SLUB: Unable to allocate memory on node %d, gfp=%#x(%pGg)\n",
> +	pr_warn("SLUB: Unable to allocate memory for CPU %u on node %d, gfp=%#x(%pGg)\n",
> +		preemptible() ? raw_smp_processor_id() : smp_processor_id(),
>  		nid, gfpflags, &gfpflags);
>  	pr_warn("  cache: %s, object size: %u, buffer size: %u, default order: %u, min order: %u\n",
>  		s->name, s->object_size, s->size, oo_order(s->oo),