From: Matthew Wilcox <willy@infradead.org>
To: Nico Pache <npache@redhat.com>
Cc: linux-kernel@vger.kernel.org, linux-mm@kvack.org,
muchun.song@linux.dev, mike.kravetz@oracle.com,
akpm@linux-foundation.org, gerald.schaefer@linux.ibm.com
Subject: Re: [RFC V2] mm: add the zero case to page[1].compound_nr in set_compound_order
Date: Wed, 14 Dec 2022 17:04:15 +0000 [thread overview]
Message-ID: <Y5oCD0gFV+Cq1JqJ@casper.infradead.org> (raw)
In-Reply-To: <20221213234505.173468-1-npache@redhat.com>
On Tue, Dec 13, 2022 at 04:45:05PM -0700, Nico Pache wrote:
> Since commit 1378a5ee451a ("mm: store compound_nr as well as
> compound_order") the page[1].compound_nr must be explicitly set to 0 if
> calling set_compound_order(page, 0).
>
> This can lead to bugs if the caller of set_compound_order(page, 0) forgets
> to explicitly set compound_nr=0. An example of this is commit ba9c1201beaa
> ("mm/hugetlb: clear compound_nr before freeing gigantic pages")
>
> Collapse these calls into the set_compound_order by utilizing branchless
> bitmaths [1].
>
> [1] https://graphics.stanford.edu/~seander/bithacks.html#ConditionalSetOrClearBitsWithoutBranching
>
> V2: slight changes to commit log and remove extra '//' in the comments
We don't usually use // comments anywhere in the kernel other than
the SPDX header.
> static inline void set_compound_order(struct page *page, unsigned int order)
> {
> + unsigned long shift = (1U << order);
Shift is a funny name for this variable. order is the shift. this is 'nr'.
> page[1].compound_order = order;
> #ifdef CONFIG_64BIT
> - page[1].compound_nr = 1U << order;
> + // Branchless conditional:
> + // order > 0 --> compound_nr = shift
> + // order == 0 --> compound_nr = 0
> + page[1].compound_nr = shift ^ (-order ^ shift) & shift;
Can the compiler see through this? Before, the compiler sees:
page[1].compound_order = 0;
page[1].compound_nr = 1U << 0;
...
page[1].compound_nr = 0;
and it can eliminate the first store. Now the compiler sees:
unsigned long shift = (1U << 0);
page[1].compound_order = order;
page[1].compound_nr = shift ^ (0 ^ shift) & shift;
Does it do the maths at compile-time, knowing that order is 0 at this
callsite and deducing that it can just store a 0?
I think it might, since shift is constant-1,
page[1].compound_nr = 1 ^ (0 ^ 1) & 1;
-> page[1].compound_nr = 1 ^ 1 & 1;
-> page[1].compound_nr = 0 & 1;
-> page[1].compound_nr = 0;
But you should run it through the compiler and check the assembly
output for __destroy_compound_gigantic_page().
next prev parent reply other threads:[~2022-12-14 17:04 UTC|newest]
Thread overview: 12+ messages / expand[flat|nested] mbox.gz Atom feed top
2022-12-13 23:45 Nico Pache
2022-12-13 23:47 ` Mike Kravetz
2022-12-13 23:53 ` Nico Pache
2022-12-14 0:27 ` Nico Pache
2022-12-14 1:02 ` Mike Kravetz
2022-12-14 6:38 ` Sidhartha Kumar
2022-12-15 1:05 ` Nico Pache
2022-12-14 17:04 ` Matthew Wilcox [this message]
2022-12-15 2:48 ` Nico Pache
2022-12-15 21:38 ` Nico Pache
2022-12-15 21:47 ` Matthew Wilcox
2022-12-15 22:02 ` Nico Pache
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