Re: [PATCH] drivers/base/node: Fix double free in register_one_node()

[David Hildenbrand <david@redhat.com>]

On 18.09.25 07:55, David Hildenbrand wrote:
> On 18.09.25 07:41, Donet Tom wrote:
>> When device_register() fails in register_node(), it calls
>> put_device(&node->dev). This triggers node_device_release(),
>> which calls kfree(to_node(dev)), thereby freeing the entire
>> node structure.
>>
>> As a result, when register_node() returns an error, the node
>> memory has already been freed. Calling kfree(node) again in
>> register_one_node() leads to a double free.
>>
>> This patch removes the redundant kfree(node) from
>> register_one_node() to prevent the double free.
>>
>> Fixes: 786eb990cfb7 ("drivers/base/node: handle error properly in register_one_node()")
>> Signed-off-by: Donet Tom <donettom@linux.ibm.com>
>> ---
>>    drivers/base/node.c | 1 -
>>    1 file changed, 1 deletion(-)
>>
>> diff --git a/drivers/base/node.c b/drivers/base/node.c
>> index 1608816de67f..6b6e55a98b79 100644
>> --- a/drivers/base/node.c
>> +++ b/drivers/base/node.c
>> @@ -885,7 +885,6 @@ int register_one_node(int nid)
>>    	error = register_node(node_devices[nid], nid);
>>    	if (error) {
>>    		node_devices[nid] = NULL;
>> -		kfree(node);
>>    		return error;
>>    	}
>>    
> 
> Yes, that matches what other users (staring at mm/memory-tiers.c) do.

I forgot

Acked-by: David Hildenbrand <david@redhat.com>

-- 
Cheers

David / dhildenb