From mboxrd@z Thu Jan 1 00:00:00 1970 Return-Path: Received: from mail-la0-f43.google.com (mail-la0-f43.google.com [209.85.215.43]) by kanga.kvack.org (Postfix) with ESMTP id 366056B0255 for ; Fri, 25 Sep 2015 16:30:28 -0400 (EDT) Received: by lacdq2 with SMTP id dq2so55186874lac.1 for ; Fri, 25 Sep 2015 13:30:27 -0700 (PDT) Received: from v094114.home.net.pl (v094114.home.net.pl. [79.96.170.134]) by mx.google.com with SMTP id c5si2441032lbp.10.2015.09.25.13.30.26 for ; Fri, 25 Sep 2015 13:30:27 -0700 (PDT) From: "Rafael J. Wysocki" Subject: Re: [PATCH V4 1/2] ACPI / EC: Fix broken 64bit big-endian users of 'global_lock' Date: Fri, 25 Sep 2015 22:58:42 +0200 Message-ID: <2524822.pQu4UKMrlb@vostro.rjw.lan> In-Reply-To: References: <4357538.Wlf88yQie6@vostro.rjw.lan> MIME-Version: 1.0 Content-Transfer-Encoding: 7Bit Content-Type: text/plain; charset="utf-8" Sender: owner-linux-mm@kvack.org List-ID: To: Viresh Kumar Cc: Johannes Berg , Greg Kroah-Hartman , Linaro Kernel Mailman List , QCA ath9k Development , Intel Linux Wireless , "linux-doc@vger.kernel.org" , Linux Kernel Mailing List , "linux-arm-kernel@lists.infradead.org" , Linux ACPI , "open list:BLUETOOTH DRIVERS" , "open list:AMD IOMMU (AMD-VI)" , "netdev@vger.kernel.org" , "open list:NETWORKING DRIVERS (WIRELESS)" , "open list:TARGET SUBSYSTEM" , "open list:ULTRA-WIDEBAND (UWB) SUBSYSTEM:" , "open list:EDAC-CORE" , Linux Memory Management List , "moderated list:SOUND - SOC LAYER / DYNAMIC AUDIO POWER MANAGEM..." On Friday, September 25, 2015 01:25:49 PM Viresh Kumar wrote: > On 25 September 2015 at 13:33, Rafael J. Wysocki wrote: > > You're going to change that into bool in the next patch, right? > > Yeah. > > > So what if bool is a byte and the field is not word-aligned > > Its between two 'unsigned long' variables today, and the struct isn't packed. > So, it will be aligned, isn't it? > > > and changing > > that byte requires a read-modify-write. How do we ensure that things remain > > consistent in that case? > > I didn't understood why a read-modify-write is special here? That's > what will happen > to most of the non-word-sized fields anyway? > > Probably I didn't understood what you meant.. Say you have three adjacent fields in a structure, x, y, z, each one byte long. Initially, all of them are equal to 0. CPU A writes 1 to x and CPU B writes 2 to y at the same time. What's the result? Thanks, Rafael -- To unsubscribe, send a message with 'unsubscribe linux-mm' in the body to majordomo@kvack.org. For more info on Linux MM, see: http://www.linux-mm.org/ . Don't email: email@kvack.org